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<html><body><h1>The XMLHttpRequest Object</h1><button type="button" onclick="loadDoc()">Request data</button><p id="demo"></p> <script>function loadDoc() { var xhttp = new XMLHttpRequest(); xhttp.onreadystatechange = function() { if (this.readyState == 4 && this.status == 200) { document.getElementById("demo").innerHTML = this.responseText; } }; xhttp.open("POST.html", "demo_post.html", true); xhttp.send();}</script></body><!-- Mirrored from www.w3schools.com/xml/tryit.asp?filename=tryajax_post by HTTrack Website Copier/3.x [XR&CO'2014], Wed, 21 Dec 2022 17:04:14 GMT --></html>